(3x-2)+(x-11)=(x-3)-(4-x)

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Solution for (3x-2)+(x-11)=(x-3)-(4-x) equation: 



(3x-2)+(x-11)=(x-3)-(4-x)

We move all terms to the left:

(3x-2)+(x-11)-((x-3)-(4-x))=0

We add all the numbers together, and all the variables

(3x-2)+(x-11)-((x-3)-(-1x+4))=0

We get rid of parentheses

3x+x-((x-3)-(-1x+4))-2-11=0



We calculate terms in parentheses: -((x-3)-(-1x+4)), so:

(x-3)-(-1x+4)

We get rid of parentheses

x+1x-3-4

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We add all the numbers together, and all the variables

4x-(2x-7)-13=0

We get rid of parentheses

4x-2x+7-13=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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