(3x-2)+(x-8)+(x)=180

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Solution for (3x-2)+(x-8)+(x)=180 equation:



(3x-2)+(x-8)+(x)=180
We move all terms to the left:
(3x-2)+(x-8)+(x)-(180)=0
We add all the numbers together, and all the variables
x+(3x-2)+(x-8)-180=0
We get rid of parentheses
x+3x+x-2-8-180=0
We add all the numbers together, and all the variables
5x-190=0
We move all terms containing x to the left, all other terms to the right
5x=190
x=190/5
x=38

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