(3x-2)+12=28

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Solution for (3x-2)+12=28 equation: 



(3x-2)+12=28

We move all terms to the left:

(3x-2)+12-(28)=0

We add all the numbers together, and all the variables

(3x-2)-16=0

We get rid of parentheses

3x-2-16=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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