(3x-2)+2(6x+32)=180

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Solution for (3x-2)+2(6x+32)=180 equation: 



(3x-2)+2(6x+32)=180

We move all terms to the left:

(3x-2)+2(6x+32)-(180)=0

We multiply parentheses

(3x-2)+12x+64-180=0

We get rid of parentheses

3x+12x-2+64-180=0

We add all the numbers together, and all the variables

15x-118=0

We move all terms containing x to the left, all other terms to the right

15x=118

x=118/15

x=7+13/15

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