(3x-2)+4(x+3)=45

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Solution for (3x-2)+4(x+3)=45 equation: 



(3x-2)+4(x+3)=45

We move all terms to the left:

(3x-2)+4(x+3)-(45)=0

We multiply parentheses

(3x-2)+4x+12-45=0

We get rid of parentheses

3x+4x-2+12-45=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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