(3x-2)+8(x+1)=100

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Solution for (3x-2)+8(x+1)=100 equation: 



(3x-2)+8(x+1)=100

We move all terms to the left:

(3x-2)+8(x+1)-(100)=0

We multiply parentheses

(3x-2)+8x+8-100=0

We get rid of parentheses

3x+8x-2+8-100=0

We add all the numbers together, and all the variables

11x-94=0

We move all terms containing x to the left, all other terms to the right

11x=94

x=94/11

x=8+6/11

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