(3x-2)-9x=4(1-3x)

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Solution for (3x-2)-9x=4(1-3x) equation: 



(3x-2)-9x=4(1-3x)

We move all terms to the left:

(3x-2)-9x-(4(1-3x))=0

We add all the numbers together, and all the variables

(3x-2)-9x-(4(-3x+1))=0

We add all the numbers together, and all the variables

-9x+(3x-2)-(4(-3x+1))=0

We get rid of parentheses

-9x+3x-(4(-3x+1))-2=0



We calculate terms in parentheses: -(4(-3x+1)), so:

4(-3x+1)

We multiply parentheses

-12x+4

Back to the equation:

-(-12x+4)



We add all the numbers together, and all the variables

-6x-(-12x+4)-2=0

We get rid of parentheses

-6x+12x-4-2=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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