(3x-2)/(3)+(2x+3)/(2)=x+(7)/(6)

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Solution for (3x-2)/(3)+(2x+3)/(2)=x+(7)/(6) equation: 



(3x-2)/(3)+(2x+3)/(2)=x+(7)/(6)

We move all terms to the left:

(3x-2)/(3)+(2x+3)/(2)-(x+(7)/(6))=0

We add all the numbers together, and all the variables

(3x-2)/3+(2x+3)/2-(+x+7/6)=0

We get rid of parentheses

(3x-2)/3+(2x+3)/2-x-7/6=0

We calculate fractions

There is no solution for this equation

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