(3x-2)/2=(3x+2)/4

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Solution for (3x-2)/2=(3x+2)/4 equation: 



(3x-2)/2=(3x+2)/4

We move all terms to the left:

(3x-2)/2-((3x+2)/4)=0

We calculate fractions


3x/()+(-((3x+2)*2)/()=0



We calculate terms in parentheses: +(-((3x+2)*2)/(), so:

-((3x+2)*2)/(

We multiply all the terms by the denominator


-((3x+2)*2)



We calculate terms in parentheses: -((3x+2)*2), so:

(3x+2)*2

We multiply parentheses

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

-6x-4

Back to the equation:

+(-6x-4)



We get rid of parentheses

3x/()-6x-4=0

We multiply all the terms by the denominator


3x-6x*()-4*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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