(3x-2)/3+(2x+3)/3=x+7/6

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Solution for (3x-2)/3+(2x+3)/3=x+7/6 equation: 



(3x-2)/3+(2x+3)/3=x+7/6

We move all terms to the left:

(3x-2)/3+(2x+3)/3-(x+7/6)=0

We add all the numbers together, and all the variables

(3x-2)/3+(2x+3)/3-(+x+7/6)=0

We get rid of parentheses

(3x-2)/3+(2x+3)/3-x-7/6=0

We calculate fractions

There is no solution for this equation

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