(3x-2)/3-(2x-5)/4=(2x-4)/8

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Solution for (3x-2)/3-(2x-5)/4=(2x-4)/8 equation: 


x in (-oo:+oo)

(3*x-2)/3-((2*x-5)/4) = (2*x-4)/8 // - (2*x-4)/8

(3*x-2)/3-((2*x-5)/4)-((2*x-4)/8) = 0

(3*x-2)/3+(-1*(2*x-5))/4+(-1*(2*x-4))/8 = 0

(4*8*(3*x-2))/(3*4*8)+(-1*3*8*(2*x-5))/(3*4*8)+(-1*3*4*(2*x-4))/(3*4*8) = 0

4*8*(3*x-2)-1*3*8*(2*x-5)-1*3*4*(2*x-4) = 0

48*x-24*x+48+56 = 0

24*x+104 = 0

(24*x+104)/(3*4*8) = 0

(24*x+104)/(3*4*8) = 0 // * 3*4*8

24*x+104 = 0

24*x+104 = 0 // - 104

24*x = -104 // : 24

x = -104/24

x = -13/3

x = -13/3

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