(3x-2)/4-(2x+3)/3=2/3-x

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Solution for (3x-2)/4-(2x+3)/3=2/3-x equation: 



(3x-2)/4-(2x+3)/3=2/3-x

We move all terms to the left:

(3x-2)/4-(2x+3)/3-(2/3-x)=0



Domain of the equation: 3-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

(3x-2)/4-(2x+3)/3-(-1x+2/3)=0

We get rid of parentheses

(3x-2)/4-(2x+3)/3+1x-2/3=0

We calculate fractions

There is no solution for this equation

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