(3x-2)/4-(2x+3)/3=2/3-x

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Solution for (3x-2)/4-(2x+3)/3=2/3-x equation:



(3x-2)/4-(2x+3)/3=2/3-x
We move all terms to the left:
(3x-2)/4-(2x+3)/3-(2/3-x)=0
Domain of the equation: 3-x)!=0
We move all terms containing x to the left, all other terms to the right
-x)!=-3
x!=-3/1
x!=-3
x∈R
We add all the numbers together, and all the variables
(3x-2)/4-(2x+3)/3-(-1x+2/3)=0
We get rid of parentheses
(3x-2)/4-(2x+3)/3+1x-2/3=0
We calculate fractions
There is no solution for this equation

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