(3x-2)/4=(x-1)/3

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Solution for (3x-2)/4=(x-1)/3 equation: 



(3x-2)/4=(x-1)/3

We move all terms to the left:

(3x-2)/4-((x-1)/3)=0

We calculate fractions


3x/()+(-((x-1)*4)/()=0



We calculate terms in parentheses: +(-((x-1)*4)/(), so:

-((x-1)*4)/(

We multiply all the terms by the denominator


-((x-1)*4)



We calculate terms in parentheses: -((x-1)*4), so:

(x-1)*4

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

-4x+4

Back to the equation:

+(-4x+4)



We get rid of parentheses

3x/()-4x+4=0

We multiply all the terms by the denominator


3x-4x*()+4*()=0

We add all the numbers together, and all the variables

3x-4x*()=0

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