(3x-2)/8=(2x-1)/6

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Solution for (3x-2)/8=(2x-1)/6 equation: 



(3x-2)/8=(2x-1)/6

We move all terms to the left:

(3x-2)/8-((2x-1)/6)=0

We calculate fractions


3x/()+(-((2x-1)*8)/()=0



We calculate terms in parentheses: +(-((2x-1)*8)/(), so:

-((2x-1)*8)/(

We multiply all the terms by the denominator


-((2x-1)*8)



We calculate terms in parentheses: -((2x-1)*8), so:

(2x-1)*8

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

-16x+8

Back to the equation:

+(-16x+8)



We get rid of parentheses

3x/()-16x+8=0

We multiply all the terms by the denominator


3x-16x*()+8*()=0

We add all the numbers together, and all the variables

3x-16x*()=0

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