(3x-2)=(14x-19)=(9x+7)

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Solution for (3x-2)=(14x-19)=(9x+7) equation: 



(3x-2)=(14x-19)=(9x+7)

We move all terms to the left:

(3x-2)-((14x-19))=0

We get rid of parentheses

3x-((14x-19))-2=0



We calculate terms in parentheses: -((14x-19)), so:

(14x-19)

We get rid of parentheses

14x-19

Back to the equation:

-(14x-19)



We get rid of parentheses

3x-14x+19-2=0

We add all the numbers together, and all the variables

-11x+17=0

We move all terms containing x to the left, all other terms to the right

-11x=-17

x=-17/-11

x=1+6/11

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