(3x-2)=3(3x-2)+1

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Solution for (3x-2)=3(3x-2)+1 equation:



(3x-2)=3(3x-2)+1
We move all terms to the left:
(3x-2)-(3(3x-2)+1)=0
We get rid of parentheses
3x-(3(3x-2)+1)-2=0
We calculate terms in parentheses: -(3(3x-2)+1), so:
3(3x-2)+1
We multiply parentheses
9x-6+1
We add all the numbers together, and all the variables
9x-5
Back to the equation:
-(9x-5)
We get rid of parentheses
3x-9x+5-2=0
We add all the numbers together, and all the variables
-6x+3=0
We move all terms containing x to the left, all other terms to the right
-6x=-3
x=-3/-6
x=1/2

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