(3x-2)=3(3x-2)+1

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Solution for (3x-2)=3(3x-2)+1 equation: 



(3x-2)=3(3x-2)+1

We move all terms to the left:

(3x-2)-(3(3x-2)+1)=0

We get rid of parentheses

3x-(3(3x-2)+1)-2=0



We calculate terms in parentheses: -(3(3x-2)+1), so:

3(3x-2)+1

We multiply parentheses

9x-6+1

We add all the numbers together, and all the variables

9x-5

Back to the equation:

-(9x-5)



We get rid of parentheses

3x-9x+5-2=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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