(3x-2)=3+2(3x-2)

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Solution for (3x-2)=3+2(3x-2) equation: 



(3x-2)=3+2(3x-2)

We move all terms to the left:

(3x-2)-(3+2(3x-2))=0

We get rid of parentheses

3x-(3+2(3x-2))-2=0



We calculate terms in parentheses: -(3+2(3x-2)), so:

3+2(3x-2)

determiningTheFunctionDomain
2(3x-2)+3

We multiply parentheses

6x-4+3

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

3x-6x+1-2=0

We add all the numbers together, and all the variables

-3x-1=0

We move all terms containing x to the left, all other terms to the right

-3x=1

x=1/-3

x=-1/3

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