(3x-2+(3x-2)*2)=2x+7

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Solution for (3x-2+(3x-2)*2)=2x+7 equation: 



(3x-2+(3x-2)*2)=2x+7

We move all terms to the left:

(3x-2+(3x-2)*2)-(2x+7)=0

We get rid of parentheses

(3x-2+(3x-2)*2)-2x-7=0



We calculate terms in parentheses: +(3x-2+(3x-2)*2), so:

3x-2+(3x-2)*2

determiningTheFunctionDomain
3x+(3x-2)*2-2

We multiply parentheses

3x+6x-4-2

We add all the numbers together, and all the variables

9x-6

Back to the equation:

+(9x-6)



We add all the numbers together, and all the variables

-2x+(9x-6)-7=0

We get rid of parentheses

-2x+9x-6-7=0

We add all the numbers together, and all the variables

7x-13=0

We move all terms containing x to the left, all other terms to the right

7x=13

x=13/7

x=1+6/7

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