(3x-2/1-3x)=(x-6/x+9)

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Solution for (3x-2/1-3x)=(x-6/x+9) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(3*x)-(2/1) = x-(6/x)+9 // - x-(6/x)+9

3*x-(3*x)-x+6/x-(2/1)-9 = 0

3*x-3*x-x+6/x-9-2 = 0

6*x^-1-1*x^1-11*x^0 = 0

(6*x^0-1*x^2-11*x^1)/(x^1) = 0 // * x^2

x^1*(6*x^0-1*x^2-11*x^1) = 0

x^1

6-x^2-11*x = 0

6-x^2-11*x = 0

DELTA = (-11)^2-(-1*4*6)

DELTA = 145

DELTA > 0

x = (145^(1/2)+11)/(-1*2) or x = (11-145^(1/2))/(-1*2)

x = (145^(1/2)+11)/(-2) or x = (11-145^(1/2))/(-2)

x in { (145^(1/2)+11)/(-2), (11-145^(1/2))/(-2)}

x in { (145^(1/2)+11)/(-2), (11-145^(1/2))/(-2) }

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