(3x-20)+(2x-15)=100

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Solution for (3x-20)+(2x-15)=100 equation: 



(3x-20)+(2x-15)=100

We move all terms to the left:

(3x-20)+(2x-15)-(100)=0

We get rid of parentheses

3x+2x-20-15-100=0

We add all the numbers together, and all the variables

5x-135=0

We move all terms containing x to the left, all other terms to the right

5x=135

x=135/5

x=27

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