(3x-20)+(3x+5)=111

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Solution for (3x-20)+(3x+5)=111 equation: 



(3x-20)+(3x+5)=111

We move all terms to the left:

(3x-20)+(3x+5)-(111)=0

We get rid of parentheses

3x+3x-20+5-111=0

We add all the numbers together, and all the variables

6x-126=0

We move all terms containing x to the left, all other terms to the right

6x=126

x=126/6

x=21

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