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(3x-22)=(2x-5)
We move all terms to the left:
(3x-22)-((2x-5))=0
We get rid of parentheses
3x-((2x-5))-22=0
We calculate terms in parentheses: -((2x-5)), so:We get rid of parentheses
(2x-5)
We get rid of parentheses
2x-5
Back to the equation:
-(2x-5)
3x-2x+5-22=0
We add all the numbers together, and all the variables
x-17=0
We move all terms containing x to the left, all other terms to the right
x=17
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