(3x-23)+(2x+32)=108

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Solution for (3x-23)+(2x+32)=108 equation: 



(3x-23)+(2x+32)=108

We move all terms to the left:

(3x-23)+(2x+32)-(108)=0

We get rid of parentheses

3x+2x-23+32-108=0

We add all the numbers together, and all the variables

5x-99=0

We move all terms containing x to the left, all other terms to the right

5x=99

x=99/5

x=19+4/5

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