(3x-23)=(2x+26)

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Solution for (3x-23)=(2x+26) equation: 



(3x-23)=(2x+26)

We move all terms to the left:

(3x-23)-((2x+26))=0

We get rid of parentheses

3x-((2x+26))-23=0



We calculate terms in parentheses: -((2x+26)), so:

(2x+26)

We get rid of parentheses

2x+26

Back to the equation:

-(2x+26)



We get rid of parentheses

3x-2x-26-23=0

We add all the numbers together, and all the variables

x-49=0

We move all terms containing x to the left, all other terms to the right

x=49

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