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(3x-23)=(2x+26)
We move all terms to the left:
(3x-23)-((2x+26))=0
We get rid of parentheses
3x-((2x+26))-23=0
We calculate terms in parentheses: -((2x+26)), so:We get rid of parentheses
(2x+26)
We get rid of parentheses
2x+26
Back to the equation:
-(2x+26)
3x-2x-26-23=0
We add all the numbers together, and all the variables
x-49=0
We move all terms containing x to the left, all other terms to the right
x=49
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