(3x-23)=(2x+29)

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Solution for (3x-23)=(2x+29) equation: 



(3x-23)=(2x+29)

We move all terms to the left:

(3x-23)-((2x+29))=0

We get rid of parentheses

3x-((2x+29))-23=0



We calculate terms in parentheses: -((2x+29)), so:

(2x+29)

We get rid of parentheses

2x+29

Back to the equation:

-(2x+29)



We get rid of parentheses

3x-2x-29-23=0

We add all the numbers together, and all the variables

x-52=0

We move all terms containing x to the left, all other terms to the right

x=52

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