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(3x-23)=(2x+38)
We move all terms to the left:
(3x-23)-((2x+38))=0
We get rid of parentheses
3x-((2x+38))-23=0
We calculate terms in parentheses: -((2x+38)), so:We get rid of parentheses
(2x+38)
We get rid of parentheses
2x+38
Back to the equation:
-(2x+38)
3x-2x-38-23=0
We add all the numbers together, and all the variables
x-61=0
We move all terms containing x to the left, all other terms to the right
x=61
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