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(3x-25)=(2x+28)
We move all terms to the left:
(3x-25)-((2x+28))=0
We get rid of parentheses
3x-((2x+28))-25=0
We calculate terms in parentheses: -((2x+28)), so:We get rid of parentheses
(2x+28)
We get rid of parentheses
2x+28
Back to the equation:
-(2x+28)
3x-2x-28-25=0
We add all the numbers together, and all the variables
x-53=0
We move all terms containing x to the left, all other terms to the right
x=53
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