(3x-25)=(2x+28)

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Solution for (3x-25)=(2x+28) equation: 



(3x-25)=(2x+28)

We move all terms to the left:

(3x-25)-((2x+28))=0

We get rid of parentheses

3x-((2x+28))-25=0



We calculate terms in parentheses: -((2x+28)), so:

(2x+28)

We get rid of parentheses

2x+28

Back to the equation:

-(2x+28)



We get rid of parentheses

3x-2x-28-25=0

We add all the numbers together, and all the variables

x-53=0

We move all terms containing x to the left, all other terms to the right

x=53

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