(3x-27)=(2x+35)

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Solution for (3x-27)=(2x+35) equation: 



(3x-27)=(2x+35)

We move all terms to the left:

(3x-27)-((2x+35))=0

We get rid of parentheses

3x-((2x+35))-27=0



We calculate terms in parentheses: -((2x+35)), so:

(2x+35)

We get rid of parentheses

2x+35

Back to the equation:

-(2x+35)



We get rid of parentheses

3x-2x-35-27=0

We add all the numbers together, and all the variables

x-62=0

We move all terms containing x to the left, all other terms to the right

x=62

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