(3x-28)+(66-x)=120

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Solution for (3x-28)+(66-x)=120 equation: 



(3x-28)+(66-x)=120

We move all terms to the left:

(3x-28)+(66-x)-(120)=0

We add all the numbers together, and all the variables

(3x-28)+(-1x+66)-120=0

We get rid of parentheses

3x-1x-28+66-120=0

We add all the numbers together, and all the variables

2x-82=0

We move all terms containing x to the left, all other terms to the right

2x=82

x=82/2

x=41

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