(3x-28)+(68-x)=180

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Solution for (3x-28)+(68-x)=180 equation: 



(3x-28)+(68-x)=180

We move all terms to the left:

(3x-28)+(68-x)-(180)=0

We add all the numbers together, and all the variables

(3x-28)+(-1x+68)-180=0

We get rid of parentheses

3x-1x-28+68-180=0

We add all the numbers together, and all the variables

2x-140=0

We move all terms containing x to the left, all other terms to the right

2x=140

x=140/2

x=70

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