(3x-28)=(2x+34)

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Solution for (3x-28)=(2x+34) equation: 



(3x-28)=(2x+34)

We move all terms to the left:

(3x-28)-((2x+34))=0

We get rid of parentheses

3x-((2x+34))-28=0



We calculate terms in parentheses: -((2x+34)), so:

(2x+34)

We get rid of parentheses

2x+34

Back to the equation:

-(2x+34)



We get rid of parentheses

3x-2x-34-28=0

We add all the numbers together, and all the variables

x-62=0

We move all terms containing x to the left, all other terms to the right

x=62

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