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(3x-3)(2x+5)=0
We multiply parentheses ..
(+6x^2+15x-6x-15)=0
We get rid of parentheses
6x^2+15x-6x-15=0
We add all the numbers together, and all the variables
6x^2+9x-15=0
a = 6; b = 9; c = -15;
Δ = b2-4ac
Δ = 92-4·6·(-15)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-21}{2*6}=\frac{-30}{12} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+21}{2*6}=\frac{12}{12} =1 $
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