(3x-3)*(2x+2)=

Solution for (3x-3)*(2x+2)= equation:

Simplifying
(3x + -3)(2x + 2) = 0

Reorder the terms:
(-3 + 3x)(2x + 2) = 0

Reorder the terms:
(-3 + 3x)(2 + 2x) = 0

Multiply (-3 + 3x) * (2 + 2x)
(-3(2 + 2x) + 3x * (2 + 2x)) = 0
((2 * -3 + 2x * -3) + 3x * (2 + 2x)) = 0
((-6 + -6x) + 3x * (2 + 2x)) = 0
(-6 + -6x + (2 * 3x + 2x * 3x)) = 0
(-6 + -6x + (6x + 6x2)) = 0

Combine like terms: -6x + 6x = 0
(-6 + 0 + 6x2) = 0
(-6 + 6x2) = 0

Solving
-6 + 6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 6x2 = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 6x2 = 0 + 6
6x2 = 0 + 6

Combine like terms: 0 + 6 = 6
6x2 = 6

Divide each side by '6'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}