(3x-3)+(2x+5)+(4x-12)=89

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Solution for (3x-3)+(2x+5)+(4x-12)=89 equation:


Simplifying
(3x + -3) + (2x + 5) + (4x + -12) = 89

Reorder the terms:
(-3 + 3x) + (2x + 5) + (4x + -12) = 89

Remove parenthesis around (-3 + 3x)
-3 + 3x + (2x + 5) + (4x + -12) = 89

Reorder the terms:
-3 + 3x + (5 + 2x) + (4x + -12) = 89

Remove parenthesis around (5 + 2x)
-3 + 3x + 5 + 2x + (4x + -12) = 89

Reorder the terms:
-3 + 3x + 5 + 2x + (-12 + 4x) = 89

Remove parenthesis around (-12 + 4x)
-3 + 3x + 5 + 2x + -12 + 4x = 89

Reorder the terms:
-3 + 5 + -12 + 3x + 2x + 4x = 89

Combine like terms: -3 + 5 = 2
2 + -12 + 3x + 2x + 4x = 89

Combine like terms: 2 + -12 = -10
-10 + 3x + 2x + 4x = 89

Combine like terms: 3x + 2x = 5x
-10 + 5x + 4x = 89

Combine like terms: 5x + 4x = 9x
-10 + 9x = 89

Solving
-10 + 9x = 89

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 9x = 89 + 10

Combine like terms: -10 + 10 = 0
0 + 9x = 89 + 10
9x = 89 + 10

Combine like terms: 89 + 10 = 99
9x = 99

Divide each side by '9'.
x = 11

Simplifying
x = 11

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