(3x-3)+(4x+2)=20

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Solution for (3x-3)+(4x+2)=20 equation: 



(3x-3)+(4x+2)=20

We move all terms to the left:

(3x-3)+(4x+2)-(20)=0

We get rid of parentheses

3x+4x-3+2-20=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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