(3x-3)/(x+2)=2

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Solution for (3x-3)/(x+2)=2 equation: 



(3x-3)/(x+2)=2

We move all terms to the left:

(3x-3)/(x+2)-(2)=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We multiply all the terms by the denominator


(3x-3)-2*(x+2)=0

We multiply parentheses

(3x-3)-2x-4=0

We get rid of parentheses

3x-2x-3-4=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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