(3x-3)/3=(7x-1)/5

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Solution for (3x-3)/3=(7x-1)/5 equation:



(3x-3)/3=(7x-1)/5
We move all terms to the left:
(3x-3)/3-((7x-1)/5)=0
We calculate fractions
3x/()+(-((7x-1)*3)/()=0
We calculate terms in parentheses: +(-((7x-1)*3)/(), so:
-((7x-1)*3)/(
We multiply all the terms by the denominator
-((7x-1)*3)
We calculate terms in parentheses: -((7x-1)*3), so:
(7x-1)*3
We multiply parentheses
21x-3
Back to the equation:
-(21x-3)
We get rid of parentheses
-21x+3
Back to the equation:
+(-21x+3)
We get rid of parentheses
3x/()-21x+3=0
We multiply all the terms by the denominator
3x-21x*()+3*()=0
We add all the numbers together, and all the variables
3x-21x*()=0

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