(3x-3)/3=(7x-1)/5

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Solution for (3x-3)/3=(7x-1)/5 equation: 



(3x-3)/3=(7x-1)/5

We move all terms to the left:

(3x-3)/3-((7x-1)/5)=0

We calculate fractions


3x/()+(-((7x-1)*3)/()=0



We calculate terms in parentheses: +(-((7x-1)*3)/(), so:

-((7x-1)*3)/(

We multiply all the terms by the denominator


-((7x-1)*3)



We calculate terms in parentheses: -((7x-1)*3), so:

(7x-1)*3

We multiply parentheses

21x-3

Back to the equation:

-(21x-3)



We get rid of parentheses

-21x+3

Back to the equation:

+(-21x+3)



We get rid of parentheses

3x/()-21x+3=0

We multiply all the terms by the denominator


3x-21x*()+3*()=0

We add all the numbers together, and all the variables

3x-21x*()=0

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