(3x-3)/6=(2x+4)/10

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Solution for (3x-3)/6=(2x+4)/10 equation: 



(3x-3)/6=(2x+4)/10

We move all terms to the left:

(3x-3)/6-((2x+4)/10)=0

We calculate fractions


3x/()+(-((2x+4)*6)/()=0



We calculate terms in parentheses: +(-((2x+4)*6)/(), so:

-((2x+4)*6)/(

We multiply all the terms by the denominator


-((2x+4)*6)



We calculate terms in parentheses: -((2x+4)*6), so:

(2x+4)*6

We multiply parentheses

12x+24

Back to the equation:

-(12x+24)



We get rid of parentheses

-12x-24

Back to the equation:

+(-12x-24)



We get rid of parentheses

3x/()-12x-24=0

We multiply all the terms by the denominator


3x-12x*()-24*()=0

We add all the numbers together, and all the variables

3x-12x*()=0

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