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(3x-3)/8+x=2
We move all terms to the left:
(3x-3)/8+x-(2)=0
We add all the numbers together, and all the variables
x+(3x-3)/8-2=0
We multiply all the terms by the denominator
x*8+(3x-3)-2*8=0
We add all the numbers together, and all the variables
x*8+(3x-3)-16=0
Wy multiply elements
8x+(3x-3)-16=0
We get rid of parentheses
8x+3x-3-16=0
We add all the numbers together, and all the variables
11x-19=0
We move all terms containing x to the left, all other terms to the right
11x=19
x=19/11
x=1+8/11
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