(3x-30)+(3x+50)+(2x+60)+2x+2x=540

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Solution for (3x-30)+(3x+50)+(2x+60)+2x+2x=540 equation: 



(3x-30)+(3x+50)+(2x+60)+2x+2x=540

We move all terms to the left:

(3x-30)+(3x+50)+(2x+60)+2x+2x-(540)=0

We add all the numbers together, and all the variables

4x+(3x-30)+(3x+50)+(2x+60)-540=0

We get rid of parentheses

4x+3x+3x+2x-30+50+60-540=0

We add all the numbers together, and all the variables

12x-460=0

We move all terms containing x to the left, all other terms to the right

12x=460

x=460/12

x=38+1/3

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