(3x-30)+(x+42)=180

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Solution for (3x-30)+(x+42)=180 equation:



(3x-30)+(x+42)=180
We move all terms to the left:
(3x-30)+(x+42)-(180)=0
We get rid of parentheses
3x+x-30+42-180=0
We add all the numbers together, and all the variables
4x-168=0
We move all terms containing x to the left, all other terms to the right
4x=168
x=168/4
x=42

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