(3x-30)+(x+42)=180

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Solution for (3x-30)+(x+42)=180 equation: 



(3x-30)+(x+42)=180

We move all terms to the left:

(3x-30)+(x+42)-(180)=0

We get rid of parentheses

3x+x-30+42-180=0

We add all the numbers together, and all the variables

4x-168=0

We move all terms containing x to the left, all other terms to the right

4x=168

x=168/4

x=42

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