(3x-30)=2(x+10)

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Solution for (3x-30)=2(x+10) equation: 



(3x-30)=2(x+10)

We move all terms to the left:

(3x-30)-(2(x+10))=0

We get rid of parentheses

3x-(2(x+10))-30=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

3x-2x-20-30=0

We add all the numbers together, and all the variables

x-50=0

We move all terms containing x to the left, all other terms to the right

x=50

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