(3x-31)+(19x-5)=90

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Solution for (3x-31)+(19x-5)=90 equation:



(3x-31)+(19x-5)=90
We move all terms to the left:
(3x-31)+(19x-5)-(90)=0
We get rid of parentheses
3x+19x-31-5-90=0
We add all the numbers together, and all the variables
22x-126=0
We move all terms containing x to the left, all other terms to the right
22x=126
x=126/22
x=5+8/11

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