(3x-32)=(2x+19)

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Solution for (3x-32)=(2x+19) equation: 



(3x-32)=(2x+19)

We move all terms to the left:

(3x-32)-((2x+19))=0

We get rid of parentheses

3x-((2x+19))-32=0



We calculate terms in parentheses: -((2x+19)), so:

(2x+19)

We get rid of parentheses

2x+19

Back to the equation:

-(2x+19)



We get rid of parentheses

3x-2x-19-32=0

We add all the numbers together, and all the variables

x-51=0

We move all terms containing x to the left, all other terms to the right

x=51

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