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(3x-32)=(x+28)
We move all terms to the left:
(3x-32)-((x+28))=0
We get rid of parentheses
3x-((x+28))-32=0
We calculate terms in parentheses: -((x+28)), so:We get rid of parentheses
(x+28)
We get rid of parentheses
x+28
Back to the equation:
-(x+28)
3x-x-28-32=0
We add all the numbers together, and all the variables
2x-60=0
We move all terms containing x to the left, all other terms to the right
2x=60
x=60/2
x=30
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