(3x-33)/(2x+26)=3

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Solution for (3x-33)/(2x+26)=3 equation: 



(3x-33)/(2x+26)=3

We move all terms to the left:

(3x-33)/(2x+26)-(3)=0



Domain of the equation: (2x+26)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-26

x!=-26/2

x!=-13

x∈R



We multiply all the terms by the denominator


(3x-33)-3*(2x+26)=0

We multiply parentheses

(3x-33)-6x-78=0

We get rid of parentheses

3x-6x-33-78=0

We add all the numbers together, and all the variables

-3x-111=0

We move all terms containing x to the left, all other terms to the right

-3x=111

x=111/-3

x=-37

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