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(3x-33)=(2x-26)
We move all terms to the left:
(3x-33)-((2x-26))=0
We get rid of parentheses
3x-((2x-26))-33=0
We calculate terms in parentheses: -((2x-26)), so:We get rid of parentheses
(2x-26)
We get rid of parentheses
2x-26
Back to the equation:
-(2x-26)
3x-2x+26-33=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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