(3x-35)=(x+15)

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Solution for (3x-35)=(x+15) equation: 



(3x-35)=(x+15)

We move all terms to the left:

(3x-35)-((x+15))=0

We get rid of parentheses

3x-((x+15))-35=0



We calculate terms in parentheses: -((x+15)), so:

(x+15)

We get rid of parentheses

x+15

Back to the equation:

-(x+15)



We get rid of parentheses

3x-x-15-35=0

We add all the numbers together, and all the variables

2x-50=0

We move all terms containing x to the left, all other terms to the right

2x=50

x=50/2

x=25

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