(3x-36)+(4x-0)=90

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Solution for (3x-36)+(4x-0)=90 equation: 



(3x-36)+(4x-0)=90

We move all terms to the left:

(3x-36)+(4x-0)-(90)=0

We add all the numbers together, and all the variables

(3x-36)+(+4x)-90=0

We get rid of parentheses

3x+4x-36-90=0

We add all the numbers together, and all the variables

7x-126=0

We move all terms containing x to the left, all other terms to the right

7x=126

x=126/7

x=18

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