(3x-36)=(2x+15)

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Solution for (3x-36)=(2x+15) equation: 



(3x-36)=(2x+15)

We move all terms to the left:

(3x-36)-((2x+15))=0

We get rid of parentheses

3x-((2x+15))-36=0



We calculate terms in parentheses: -((2x+15)), so:

(2x+15)

We get rid of parentheses

2x+15

Back to the equation:

-(2x+15)



We get rid of parentheses

3x-2x-15-36=0

We add all the numbers together, and all the variables

x-51=0

We move all terms containing x to the left, all other terms to the right

x=51

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